VidPro
Flashlight Enthusiast
I keep going over this in my mind, seems right, but then it goes wrong, so i need mental assistance and math and science.
Here is the Idea, and it has been done before, with good results, but mabey not with my specs.
a 6Volt Solar cell, and a Li-Ion battery, Ignore the protection and charge alogrythm, i have that covered, its all about the solar cells discharge when dark.
When the solar cells are dark, they will drain the battery about 1/10th to 1/20th of what they could put in when they are fully sun lite.
so a diode is normally used to prevent this minor drain. but diodes have a voltage drop, and even the measley .3v voltage drop on a very low voltage system is drastic reduction in amperage when charging with full sun.
so .3v is nothing to a 12V system with 18-20V solar pannels, but in a single li-ion charge situation it is a LOT.
before i go on about the mosfet, one trick i did was put a RELAY in with a Photon resister, the relay took only 100ma in this particular system, and the whole (BIG) system (because of no diode) output 1/5th more total amperage to the battery. so this old stupid method was VERY efficient, light was required to hit the photo resister, so it was good for locked down application.
ok the mosfet, so instead of a .3v votlage drop, you toss in a mosfet, when there is power on the solar cell, the gate triggers, and the mosfet goes way low resistance, and its more efficinet than a diode, and there is a diode path in the mosfet.
But wait
ahh, and here is the mind bend, when the mosfet is at low resistance, then the battery is freely flowing in the other direction, so what is to stop the battery from keeping the mosfet gate open?
while the mosfet has diode properties, doesnt it go almost straight through connected (not one way street) when its closed?
so
how do i get the most straight through least resistance connection, and still have disconnection when the solar cells are dark and not outputting anything, but the battery is still existing and in the sence of having the least resistance, is very well connected to the solar cell?
Here is the Idea, and it has been done before, with good results, but mabey not with my specs.
a 6Volt Solar cell, and a Li-Ion battery, Ignore the protection and charge alogrythm, i have that covered, its all about the solar cells discharge when dark.
When the solar cells are dark, they will drain the battery about 1/10th to 1/20th of what they could put in when they are fully sun lite.
so a diode is normally used to prevent this minor drain. but diodes have a voltage drop, and even the measley .3v voltage drop on a very low voltage system is drastic reduction in amperage when charging with full sun.
so .3v is nothing to a 12V system with 18-20V solar pannels, but in a single li-ion charge situation it is a LOT.
before i go on about the mosfet, one trick i did was put a RELAY in with a Photon resister, the relay took only 100ma in this particular system, and the whole (BIG) system (because of no diode) output 1/5th more total amperage to the battery. so this old stupid method was VERY efficient, light was required to hit the photo resister, so it was good for locked down application.
ok the mosfet, so instead of a .3v votlage drop, you toss in a mosfet, when there is power on the solar cell, the gate triggers, and the mosfet goes way low resistance, and its more efficinet than a diode, and there is a diode path in the mosfet.
But wait
ahh, and here is the mind bend, when the mosfet is at low resistance, then the battery is freely flowing in the other direction, so what is to stop the battery from keeping the mosfet gate open?
while the mosfet has diode properties, doesnt it go almost straight through connected (not one way street) when its closed?
so
how do i get the most straight through least resistance connection, and still have disconnection when the solar cells are dark and not outputting anything, but the battery is still existing and in the sence of having the least resistance, is very well connected to the solar cell?
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